5x^2+4x+112=526

Solution for 5x^2+4x+112=526 equation:

5x^2+4x+112=526

We move all terms to the left:

5x^2+4x+112-(526)=0

We add all the numbers together, and all the variables

5x^2+4x-414=0

a = 5; b = 4; c = -414;
Δ = b2-4ac
Δ = 42-4·5·(-414)
Δ = 8296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8296}=\sqrt{4*2074}=\sqrt{4}*\sqrt{2074}=2\sqrt{2074}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{2074}}{2*5}=\frac{-4-2\sqrt{2074}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{2074}}{2*5}=\frac{-4+2\sqrt{2074}}{10}
$